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1.4x^2+x^2-53.3=0
We add all the numbers together, and all the variables
2.4x^2-53.3=0
a = 2.4; b = 0; c = -53.3;
Δ = b2-4ac
Δ = 02-4·2.4·(-53.3)
Δ = 511.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{511.68}}{2*2.4}=\frac{0-\sqrt{511.68}}{4.8} =-\frac{\sqrt{}}{4.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{511.68}}{2*2.4}=\frac{0+\sqrt{511.68}}{4.8} =\frac{\sqrt{}}{4.8} $
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